1Z0-805 덤프 Oracle 자격증 덤프

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시험 번호/코드: 1Z0-805

시험 이름: Oracle (Upgrade to Java SE 7 Programmer)

우리ITExamDump 사이트에서Oracle 1Z0-805관련자료의 일부 문제와 답 등 샘플을 제공함으로 여러분은 무료로 다운받아 체험해보실 수 있습니다.체험 후 우리의ITExamDump에 신뢰감을 느끼게 됩니다.빨리 우리 ITExamDump의 덤프를 만나보세요.

1Z0-805 덤프무료샘플다운로드하기: http://www.itexamdump.com/1Z0-805.html

NO.1 Given the code fragment:
private static void copyContents (File source, File target) {
try {inputStream fis = new FileInputStream(source);
outputStream fos = new FileOutputStream (target);
byte [] buf = new byte [8192]; int i;
while ((i = fis.read(buf)) != -1) {
fos.write (buf, 0, i);
}
//insert code fragment here. Line **
System.out.println ("Successfully copied");
}
Which code fragments, when inserted independently at line **, enable the code to compile?
A. }catch (IOException | NoSuchFileException e) { System.out.println(e); }
B. } catch (IOException | IndexOutOfBoundException e) { System.out.println(e); }
C. } catch (Exception | IOException | FileNotFoundException e ) { System.out.println(e); }
D. } catch (NoSuchFileException e ) { System.out.println(e); }
E. } catch (InvalidPathException | IOException e) { System.out.println(e); }
Answer: B,D,E

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NO.2 Which code fragments print 1?
A. String arr [] = {"1", "2", "3"}; List <? extendsString > arrList = new LinkedList <> (Arrays.asList (arr));
System.out.println (arrList.get (0));
B. String arr [] = {"1", "2", "3"}; List <Integer> arrList = new LinkedList <> (Arrays.asList (arr));
System.out.println (arrList.get (0));
C. String arr [] = {"1", "2", "3"}; List <?> arrList = new LinkedList <> (Arrays.asList (arr)); System.out.println
(arrList.get (0));
D. String arr [] = {"1","2","3"}; List <?> arrList = new LinkedList <?>(Arrays.asList (arr)); System.out.println
(arrList.get (0));
E. String arr [] = {"1","2","3"}; List <Integer> extendsString > arrList =new LinkedList <Integer>
(Arrays.asList (arr)); System.out.println (arrList.get (0));
Answer: A,C

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NO.3 Given the code fragment: public class Test {
public static void main (String [] args) {
Path path1 = Paths.get("D:\\sys\\asm\\.\\data\\..\\..\\mfg\\production.log");
System.out.println(path1.normalize());
System.out.println(path1.getNameCount());
}
}
What is the result?
A. D:\sys\mfg\production.log 8
B. D:\\sys\\asm\\.\\data\\. . \\mfg\\production.log 6
C. D: \\sys\\asm\\.\\data\\. . \\mfg\\production.log 8
D. D: \sys\mfg\production.log 4
E. D: \\ sys\\asm\\data\\mfg\\production.log 6
Answer: A

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NO.4 Given the code fragment:
public static void main(String[] args) {
String source = "d:\\company\\info.txt";
String dest = "d:\\company\\emp\\info.txt";
//insert code fragment here Line **
} catch (IOException e) {
System.err.println ("Caught IOException: " + e.getmessage();
}
}
Which two try statements, when inserted at line **, enable the code to successfully move the file info.txt to
the destination directory, even if a file by the same name already exists in the destination directory?
A. try {FileChannel in = new FileInputStream(source).getChannel(); FileChannel out = new
FileOutputStream(dest).getChannel (); in.transferTo (0, in.size(), out);
B. try {Files.copy(Paths.get(source), Paths.get(dest)); Files.delete(Paths.get(source));
C. try {Files.copy(Paths.get(source), Paths.get(dest)); Files.delete(Paths.get(source));
D. try {Files.move(Paths.get(source),Paths.get(dest));
E. try {BufferedReader br = Files.newBufferedReader(Paths.get(source), Charset.forName ("UTF8"));
BufferedWriter bw = Files.newBufferedWriter (Paths.get(dest), Charset.forName ("UTF-8")); String record
= ""; while ((record = br.readLine()) != null){ bw.write (record); bw.newLine(); }
Files.delete(Paths.get(source));
Answer: B,D

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NO.5 Given three resource bundles with these values set for menu1: ( The default resource bundle is
written in US English.)
English US resource Bundle Menu1 = small
French resource Bundle Menu1 = petit
Chinese Resource Bundle Menu = 1
And given the code fragment:
Locale.setDefault (new Locale("es", "ES")); // Set default to Spanish and Spain loc1 = Locale.getDefault();
ResourceBundle messages = ResourceBundle.getBundle ("messageBundle", loc1); System.out.println
(messages.getString("menu1")); What is the result?
A. No message is printed
B. petit
C. :
D. Small
E. A runtime error is produced
Answer: E

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NO.6 What design pattern does the Drivermanager.getconnection () method characterize?
A. DAO
B. Factory
C. Singleton
D. composition
Answer: B

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NO.7 Given the code fragment:
List<Person> pList = new CopyOnWriteArrayList<Person>();
Which statement is true?
A. Read access to the List should be synchronized.
B. Write access to the List should be synchronized.
C. Person objects retrieved from the List are thread-safe.
D. A Person object retrieved from the List is copied when written to.
E. Multiple threads can safely delete Person objects from the List.
Answer: C

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NO.8 Which statement is true about the take method defined in the WatchService interface?
A. Retrieves and removes the next watch key, or returns null of none are present.
B. Retrieves and removes the next watch key. If a queued key is not immediately available, the program
waits for the specified wait time.
C. Retrieves and removes the next watch key: waits if no key is yet present.
D. Retrieves and removes all pending events for the watch key, returning a list of the events that were
retrieved.
Answer: C

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NO.9 You are using a database from XY/Data. What is a prerequisite for connecting to the database using a
JDBC 4.0 driver from XY/Data?
A. Use the JDBC DriverManager.loadDriver method.
B. Put the XY/data driver into the classpath of your application.
C. Create an instance of the XY/Data driver class using the new keyword.
D. Create an Implementation of DriverManager that extends the XY/Data driver
Answer: B

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NO.10 Which two statements are true about the walkFileTree method of the files class?
A. The file tree traversal is breadth-first with the given FileVisitor invoked for each file encountered.
B. If the file is a directory, and if that directory could not be opened, the postVisitFileFailed method is
invoked with the I/O exception.
C. The maxDepth parameter s value is the maximum number of directories to visit.
D. By default, symbolic links are not automatically followed by the method.
Answer: C,D

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NO.11 Given the code fragment:
dataFormat df;
Which statement defines a new DataFormat object that displays the default date format for the UK
Locale?
A. df = DateFormat.getDateInstance (DateFormat.DEFAULT, Locale(UK));
B. df = DateFormat.getDateInstance (DateFormat.DEFAULT, UK);
C. df = DateFormat.getDateInstance (DateFormat.DEFAULT, Locale.UK);
D. df = new DateFormat.getDataInstance (DataFormat.DEFAULT, Locale.UK);
E. df = new DateFormat.getDateInstance (DateFormat.DEFAULT, Locale(UK));
Answer: C

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NO.12 Given a resource bundle MessageBundle, what is the name of the default bundle file?
A. MessageBundle.profile
B. MessageBundle.xml
C. MessageBundle.java
D. MessageBundle.properties
Answer: D

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NO.13 Given the following code fragment:
public class Calc {
public static void main (String [] args) {
//* insert code here Line ** System.out.print("The decimal value is" + var);
}
}
Which three code fragments, when inserted independently at line **, enable the code to compile/
A. int var = 0b_1001;
B. long var = 0b100_01L;
C. float var = 0b10_01;
D. float var = 0b10_01F;
E. double var = 0b10_01;
F. double var = 0b10_01D;
Answer: B,C,E

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NO.14 Given the fragment:
public class CustomerApplication {
public static void main (String [] args) {
CustomerDAO custDao = new CustomerDAOMemoryImp1 ();
// . . . other methods
} }
Which two valid alternatives to line 3 would decouple this application from a specific implementation of
customerDAO?
A. CustomerDAO custDao = new customerDAO();
B. CustomerDAO custDao = (CustomerDAO) new object();
C. CustomerDAO custDao = CustomerDAO.getInstance();
D. CustomerDAO custDao = (CustomerDAO) new CustomerDAOmemoryImp1();
E. CustomerDAO custDao = CustomerDAOFactory.getInstance();
Answer: C,E

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NO.15 Given:
import java.util.*; public class StringApp { public static void main (String [] args) { Set <String> set = new
TreeSet <> (); set.add("X"); set.add("Y"); set.add("X"); set.add("Y"); set.add("X"); Iterator <String> it =
set.iterator (); int count = 0; while (it.hasNext()) { switch (it.next()){ case "X": System.out.print("X "); break;
case "Y": System.out.print("Y "); break; } count++; } System.out.println ("\ncount = " + count); } }
What is the result?
A. X X Y X Y count = 5
B. X Y X Y count = 4
C. X Y count = s
D. X Y count = 2
Answer: D

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